Hm11b5b9 Mandolinen-Akkord — Diagramm und Tabs in Irish-Stimmung

Kurze Antwort: Hm11b5b9 ist ein H Moll 11♭5♭9-Akkord mit den Noten H, D, F, A, C, E. In Irish-Stimmung gibt es 254 Griffvarianten. Siehe Diagramme unten.

Auch bekannt als: Hm11°5b9, H−11b5b9, H−11°5b9

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Wie spielt man Hm11b5b9 auf Mandolin

Hm11^b5b9, Hm11^°5b9, H−11^b5b9, H−11^°5b9

Noten: H, D, F, A, C, E

5,4,2,3,0,0,0,0 (4312....)

5,4,3,2,0,0,0,0 (4321....)

x,4,3,2,3,0,0,0 (x4213...)

x,4,2,3,3,0,0,0 (x4123...)

5,4,0,3,7,0,0,0 (32.14...)

5,4,3,0,7,0,0,0 (321.4...)

5,4,2,0,0,0,3,0 (431...2.)

5,4,0,2,0,0,3,0 (43.1..2.)

5,4,0,3,0,0,2,0 (43.2..1.)

5,4,3,0,0,0,2,0 (432...1.)

x,4,2,3,0,3,0,0 (x412.3..)

x,4,3,2,0,3,0,0 (x421.3..)

5,4,0,3,0,7,0,0 (32.1.4..)

5,4,3,0,0,7,0,0 (321..4..)

5,4,3,0,0,0,0,2 (432....1)

5,4,0,0,0,0,2,3 (43....12)

5,4,0,0,0,0,3,2 (43....21)

5,4,0,3,0,0,0,2 (43.2...1)

5,4,0,2,0,0,0,3 (43.1...2)

5,4,2,0,0,0,0,3 (431....2)

x,4,2,0,3,0,3,0 (x41.2.3.)

x,4,3,0,0,3,2,0 (x42..31.)

x,4,0,3,0,3,2,0 (x4.2.31.)

x,4,3,0,3,0,2,0 (x42.3.1.)

x,4,0,2,0,3,3,0 (x4.1.23.)

x,4,0,3,3,0,2,0 (x4.23.1.)

x,4,2,0,0,3,3,0 (x41..23.)

x,4,0,2,3,0,3,0 (x4.12.3.)

5,4,0,0,0,7,3,0 (32...41.)

5,4,0,0,7,0,3,0 (32..4.1.)

x,4,2,0,0,3,0,3 (x41..2.3)

x,4,3,0,0,3,0,2 (x42..3.1)

x,4,2,0,3,0,0,3 (x41.2..3)

x,4,0,2,3,0,0,3 (x4.12..3)

x,4,0,0,0,3,3,2 (x4...231)

x,4,0,3,0,3,0,2 (x4.2.3.1)

x,4,0,0,3,0,3,2 (x4..2.31)

x,4,0,0,3,0,2,3 (x4..2.13)

x,4,0,2,0,3,0,3 (x4.1.2.3)

x,4,0,0,0,3,2,3 (x4...213)

x,4,3,0,3,0,0,2 (x42.3..1)

x,4,0,3,3,0,0,2 (x4.23..1)

5,4,0,0,0,7,0,3 (32...4.1)

5,4,0,0,7,0,0,3 (32..4..1)

5,4,3,2,x,0,0,0 (4321x...)

5,4,2,3,x,0,0,0 (4312x...)

5,4,2,3,0,0,x,0 (4312..x.)

5,4,3,2,0,0,x,0 (4321..x.)

5,4,2,3,0,0,0,x (4312...x)

5,4,3,2,0,0,0,x (4321...x)

5,4,3,2,0,x,0,0 (4321.x..)

5,4,2,3,0,x,0,0 (4312.x..)

x,4,2,3,3,0,x,0 (x4123.x.)

x,4,3,2,3,0,x,0 (x4213.x.)

x,4,2,3,3,0,0,x (x4123..x)

x,4,3,2,3,0,0,x (x4213..x)

5,4,3,0,7,0,x,0 (321.4.x.)

5,4,0,3,7,0,0,x (32.14..x)

5,4,3,0,7,0,0,x (321.4..x)

5,4,x,3,7,0,0,0 (32x14...)

5,4,3,x,7,0,0,0 (321x4...)

5,4,0,3,7,0,x,0 (32.14.x.)

5,4,x,2,0,0,3,0 (43x1..2.)

5,4,2,0,0,x,3,0 (431..x2.)

5,4,3,0,0,x,2,0 (432..x1.)

5,4,0,3,0,x,2,0 (43.2.x1.)

5,4,3,0,x,0,2,0 (432.x.1.)

5,4,0,3,x,0,2,0 (43.2x.1.)

5,4,3,x,0,0,2,0 (432x..1.)

5,4,2,x,0,0,3,0 (431x..2.)

5,4,x,3,0,0,2,0 (43x2..1.)

5,4,0,2,x,0,3,0 (43.1x.2.)

5,4,3,0,0,0,2,x (432...1x)

5,4,2,0,0,0,3,x (431...2x)

5,4,0,2,0,0,3,x (43.1..2x)

5,4,0,3,0,0,2,x (43.2..1x)

5,4,0,2,0,x,3,0 (43.1.x2.)

5,4,2,0,x,0,3,0 (431.x.2.)

x,4,2,3,0,3,x,0 (x412.3x.)

x,4,3,2,0,3,x,0 (x421.3x.)

x,4,2,3,0,3,0,x (x412.3.x)

x,4,3,2,0,3,0,x (x421.3.x)

5,4,x,3,0,7,0,0 (32x1.4..)

5,4,3,x,0,7,0,0 (321x.4..)

5,4,3,0,0,7,x,0 (321..4x.)

5,4,0,3,0,7,0,x (32.1.4.x)

5,4,3,0,0,7,0,x (321..4.x)

5,4,0,3,0,7,x,0 (32.1.4x.)

5,4,2,0,0,x,0,3 (431..x.2)

5,4,0,0,0,x,3,2 (43...x21)

5,4,0,0,x,0,3,2 (43..x.21)

5,4,3,x,0,0,0,2 (432x...1)

5,4,0,3,x,0,0,2 (43.2x..1)

5,4,x,0,0,0,2,3 (43x...12)

5,4,0,2,0,0,x,3 (43.1..x2)

5,4,0,x,0,0,2,3 (43.x..12)

5,4,3,0,x,0,0,2 (432.x..1)

5,4,0,3,0,x,0,2 (43.2.x.1)

5,4,x,2,0,0,0,3 (43x1...2)

5,4,3,0,0,x,0,2 (432..x.1)

5,4,0,0,x,0,2,3 (43..x.12)

5,4,0,0,0,x,2,3 (43...x12)

5,4,0,3,0,0,x,2 (43.2..x1)

5,4,x,0,0,0,3,2 (43x...21)

5,4,2,x,0,0,0,3 (431x...2)

5,4,3,0,0,0,x,2 (432...x1)

5,4,x,3,0,0,0,2 (43x2...1)

5,4,2,0,x,0,0,3 (431.x..2)

5,4,0,x,0,0,3,2 (43.x..21)

5,4,0,2,0,x,0,3 (43.1.x.2)

5,4,2,0,0,0,x,3 (431...x2)

5,4,0,2,x,0,0,3 (43.1x..2)

x,4,3,0,3,0,2,x (x42.3.1x)

x,4,x,2,3,0,3,0 (x4x12.3.)

x,4,x,3,0,3,2,0 (x4x2.31.)

x,4,0,3,3,0,2,x (x4.23.1x)

x,4,3,0,0,3,2,x (x42..31x)

x,4,2,x,0,3,3,0 (x41x.23.)

x,4,3,x,0,3,2,0 (x42x.31.)

x,4,x,2,0,3,3,0 (x4x1.23.)

x,4,x,3,3,0,2,0 (x4x23.1.)

x,4,3,x,3,0,2,0 (x42x3.1.)

x,4,2,x,3,0,3,0 (x41x2.3.)

x,4,0,3,0,3,2,x (x4.2.31x)

x,4,2,0,3,0,3,x (x41.2.3x)

x,4,0,2,0,3,3,x (x4.1.23x)

x,4,2,0,0,3,3,x (x41..23x)

x,4,0,2,3,0,3,x (x4.12.3x)

5,4,0,0,7,0,3,x (32..4.1x)

5,4,0,0,0,7,3,x (32...41x)

5,4,x,0,0,7,3,0 (32x..41.)

5,4,x,0,7,0,3,0 (32x.4.1.)

5,4,0,x,7,0,3,0 (32.x4.1.)

5,4,0,x,0,7,3,0 (32.x.41.)

x,4,x,0,3,0,2,3 (x4x.2.13)

x,4,2,x,0,3,0,3 (x41x.2.3)

x,4,3,0,3,0,x,2 (x42.3.x1)

x,4,2,0,0,3,x,3 (x41..2x3)

x,4,3,0,0,3,x,2 (x42..3x1)

x,4,0,3,0,3,x,2 (x4.2.3x1)

x,4,x,0,0,3,2,3 (x4x..213)

x,4,x,2,0,3,0,3 (x4x1.2.3)

x,4,x,0,3,0,3,2 (x4x.2.31)

x,4,0,2,0,3,x,3 (x4.1.2x3)

x,4,0,x,3,0,3,2 (x4.x2.31)

x,4,2,0,3,0,x,3 (x41.2.x3)

x,4,0,3,3,0,x,2 (x4.23.x1)

x,4,0,x,3,0,2,3 (x4.x2.13)

x,4,0,2,3,0,x,3 (x4.12.x3)

x,4,2,x,3,0,0,3 (x41x2..3)

x,4,x,3,0,3,0,2 (x4x2.3.1)

x,4,x,2,3,0,0,3 (x4x12..3)

x,4,3,x,3,0,0,2 (x42x3..1)

x,4,0,x,0,3,2,3 (x4.x.213)

x,4,x,3,3,0,0,2 (x4x23..1)

x,4,x,0,0,3,3,2 (x4x..231)

x,4,3,x,0,3,0,2 (x42x.3.1)

x,4,0,x,0,3,3,2 (x4.x.231)

5,4,x,0,0,7,0,3 (32x..4.1)

5,4,0,x,0,7,0,3 (32.x.4.1)

5,4,x,0,7,0,0,3 (32x.4..1)

5,4,0,x,7,0,0,3 (32.x4..1)

5,4,0,0,0,7,x,3 (32...4x1)

5,4,0,0,7,0,x,3 (32..4.x1)

7,x,7,9,8,7,7,10 (1x132114)

7,x,7,9,7,8,10,7 (1x131241)

7,x,7,9,8,7,10,7 (1x132141)

7,x,10,9,7,8,7,7 (1x431211)

7,x,10,9,8,7,7,7 (1x432111)

7,x,7,9,7,8,7,10 (1x131214)

5,4,3,2,0,x,x,0 (4321.xx.)

5,4,3,2,0,x,0,x (4321.x.x)

5,4,2,3,0,x,0,x (4312.x.x)

5,4,3,2,x,0,0,x (4321x..x)

5,4,2,3,x,0,0,x (4312x..x)

5,4,2,3,0,x,x,0 (4312.xx.)

5,4,3,2,x,0,x,0 (4321x.x.)

5,4,2,3,x,0,x,0 (4312x.x.)

5,4,3,0,7,0,x,x (321.4.xx)

5,4,3,x,7,0,0,x (321x4..x)

5,4,x,3,7,0,0,x (32x14..x)

5,4,3,x,7,0,x,0 (321x4.x.)

5,4,x,3,7,0,x,0 (32x14.x.)

5,4,0,3,7,0,x,x (32.14.xx)

5,4,3,x,0,x,2,0 (432x.x1.)

5,4,0,2,0,x,3,x (43.1.x2x)

5,4,2,x,x,0,3,0 (431xx.2.)

5,4,x,2,0,x,3,0 (43x1.x2.)

5,4,2,x,0,x,3,0 (431x.x2.)

5,4,x,3,x,0,2,0 (43x2x.1.)

5,4,3,x,x,0,2,0 (432xx.1.)

5,4,x,3,0,x,2,0 (43x2.x1.)

5,4,x,2,x,0,3,0 (43x1x.2.)

5,4,3,0,0,x,2,x (432..x1x)

5,4,0,3,0,x,2,x (43.2.x1x)

5,4,3,0,x,0,2,x (432.x.1x)

5,4,0,3,x,0,2,x (43.2x.1x)

5,4,2,0,0,x,3,x (431..x2x)

5,4,0,2,x,0,3,x (43.1x.2x)

5,4,2,0,x,0,3,x (431.x.2x)

5,4,0,3,0,7,x,x (32.1.4xx)

5,4,3,0,0,7,x,x (321..4xx)

5,4,3,x,0,7,x,0 (321x.4x.)

5,4,3,x,0,7,0,x (321x.4.x)

5,4,x,3,0,7,0,x (32x1.4.x)

5,4,x,3,0,7,x,0 (32x1.4x.)

5,4,0,2,x,0,x,3 (43.1x.x2)

5,4,0,2,0,x,x,3 (43.1.xx2)

5,4,2,0,0,x,x,3 (431..xx2)

5,4,0,3,0,x,x,2 (43.2.xx1)

5,4,3,0,x,0,x,2 (432.x.x1)

5,4,0,3,x,0,x,2 (43.2x.x1)

5,4,0,x,x,0,3,2 (43.xx.21)

5,4,x,3,0,x,0,2 (43x2.x.1)

5,4,3,x,0,x,0,2 (432x.x.1)

5,4,2,x,0,x,0,3 (431x.x.2)

5,4,2,0,x,0,x,3 (431.x.x2)

5,4,x,2,0,x,0,3 (43x1.x.2)

5,4,x,0,x,0,3,2 (43x.x.21)

5,4,3,0,0,x,x,2 (432..xx1)

5,4,2,x,x,0,0,3 (431xx..2)

5,4,x,0,0,x,3,2 (43x..x21)

5,4,x,2,x,0,0,3 (43x1x..2)

5,4,x,3,x,0,0,2 (43x2x..1)

5,4,3,x,x,0,0,2 (432xx..1)

5,4,0,x,0,x,2,3 (43.x.x12)

5,4,x,0,0,x,2,3 (43x..x12)

5,4,0,x,0,x,3,2 (43.x.x21)

5,4,0,x,x,0,2,3 (43.xx.12)

5,4,x,0,x,0,2,3 (43x.x.12)

5,4,0,x,7,0,3,x (32.x4.1x)

5,4,0,x,0,7,3,x (32.x.41x)

5,4,x,0,7,0,3,x (32x.4.1x)

5,4,x,0,0,7,3,x (32x..41x)

5,4,x,x,0,7,3,0 (32xx.41.)

5,4,x,x,7,0,3,0 (32xx4.1.)

7,x,7,9,8,7,10,x (1x13214x)

7,x,10,9,8,7,7,x (1x43211x)

7,x,10,9,7,8,7,x (1x43121x)

7,x,7,9,7,8,10,x (1x13124x)

5,4,0,x,0,7,x,3 (32.x.4x1)

5,4,x,x,7,0,0,3 (32xx4..1)

5,4,x,x,0,7,0,3 (32xx.4.1)

5,4,x,0,7,0,x,3 (32x.4.x1)

5,4,x,0,0,7,x,3 (32x..4x1)

5,4,0,x,7,0,x,3 (32.x4.x1)

7,x,x,9,8,7,10,7 (1xx32141)

7,x,x,9,7,8,10,7 (1xx31241)

7,x,10,9,7,8,x,7 (1x4312x1)

7,x,7,9,8,7,x,10 (1x1321x4)

7,x,7,9,7,8,x,10 (1x1312x4)

7,x,x,9,8,7,7,10 (1xx32114)

7,x,10,9,8,7,x,7 (1x4321x1)

7,x,x,9,7,8,7,10 (1xx31214)

Kurzübersicht

Der Hm11b5b9-Akkord enthält die Noten: H, D, F, A, C, E
In Irish-Stimmung gibt es 254 Griffvarianten
Auch geschrieben als: Hm11°5b9, H−11b5b9, H−11°5b9
Jedes Diagramm zeigt die Fingerposition auf dem Mandolin Griffbrett

Häufig gestellte Fragen

Was ist der Hm11b5b9-Akkord auf der Mandolin?

Hm11b5b9 ist ein H Moll 11♭5♭9-Akkord. Er enthält die Noten H, D, F, A, C, E. Auf der Mandolin in Irish-Stimmung gibt es 254 Griffmöglichkeiten.

Wie spielt man Hm11b5b9 auf der Mandolin?

Um Hm11b5b9 in Irish-Stimmung zu spielen, verwenden Sie eine der 254 Griffvarianten oben. Jedes Diagramm zeigt die Fingerposition auf dem Griffbrett.

Welche Noten enthält der Hm11b5b9-Akkord?

Der Hm11b5b9-Akkord enthält die Noten: H, D, F, A, C, E.

Wie viele Griffmöglichkeiten gibt es für Hm11b5b9?

In Irish-Stimmung gibt es 254 Griffvarianten für Hm11b5b9. Jede nutzt eine andere Position auf dem Griffbrett mit denselben Noten: H, D, F, A, C, E.

Welche anderen Bezeichnungen gibt es für Hm11b5b9?

Hm11b5b9 ist auch bekannt als Hm11°5b9, H−11b5b9, H−11°5b9. Dies sind verschiedene Schreibweisen für denselben Akkord: H, D, F, A, C, E.